Definition. Greatest natural number, by which the numbers a and b are divided without remainder, is called greatest common divisor (GCD) these numbers.
Let's find the largest common divisor numbers 24 and 35.
The divisors of 24 are the numbers 1, 2, 3, 4, 6, 8, 12, 24, and the divisors of 35 are the numbers 1, 5, 7, 35.
We see that the numbers 24 and 35 have only one common divisor - the number 1. Such numbers are called mutually prime.
Definition. Natural numbers are called mutually prime, if their greatest common divisor (GCD) is 1.
Greatest Common Divisor (GCD) can be found without writing out all the divisors of the given numbers.
Let's factor the numbers 48 and 36 and get:
48 = 2 * 2 * 2 * 2 * 3, 36 = 2 * 2 * 3 * 3.
From the factors included in the expansion of the first of these numbers, we cross out those that are not included in the expansion of the second number (i.e., two twos).
The factors remaining are 2 * 2 * 3. Their product is equal to 12. This number is the greatest common divisor of the numbers 48 and 36. The greatest common divisor of three or more numbers is also found.
To find greatest common divisor
2) from the factors included in the expansion of one of these numbers, cross out those that are not included in the expansion of other numbers;
3) find the product of the remaining factors.
If all given numbers are divisible by one of them, then this number is greatest common divisor given numbers.
For example, the greatest common divisor of the numbers 15, 45, 75 and 180 is the number 15, since all other numbers are divisible by it: 45, 75 and 180.
Least common multiple (LCM)
Definition. Least common multiple (LCM) natural numbers a and b is the smallest natural number that is a multiple of both a and b. The least common multiple (LCM) of the numbers 75 and 60 can be found without writing down the multiples of these numbers in a row. To do this, let's decompose 75 and 60 into prime factors: 75 = 3 * 5 * 5, and 60 = 2 * 2 * 3 * 5.
Let's write down the factors included in the expansion of the first of these numbers, and add to them the missing factors 2 and 2 from the expansion of the second number (i.e., we combine the factors).
We get five factors 2 * 2 * 3 * 5 * 5, the product of which is 300. This number is the least common multiple of the numbers 75 and 60.
They also find the least common multiple of three or more numbers.
To find least common multiple several natural numbers, you need:
1) factor them into prime factors;
2) write down the factors included in the expansion of one of the numbers;
3) add to them the missing factors from the expansions of the remaining numbers;
4) find the product of the resulting factors.
Note that if one of these numbers is divisible by all other numbers, then this number is the least common multiple of these numbers.
For example, the least common multiple of the numbers 12, 15, 20, and 60 is 60 because it is divisible by all of those numbers.
Pythagoras (VI century BC) and his students studied the question of the divisibility of numbers. Number, equal to the sum They called all its divisors (without the number itself) a perfect number. For example, the numbers 6 (6 = 1 + 2 + 3), 28 (28 = 1 + 2 + 4 + 7 + 14) are perfect. The next perfect numbers are 496, 8128, 33,550,336. The Pythagoreans only knew the first three perfect numbers. The fourth - 8128 - became known in the 1st century. n. e. The fifth - 33,550,336 - was found in the 15th century. By 1983, 27 perfect numbers were already known. But scientists still don’t know whether there are odd perfect numbers or whether there is a largest perfect number.
The interest of ancient mathematicians in prime numbers stems from the fact that any number is either prime or can be represented as a product prime numbers, i.e. prime numbers are like bricks from which the rest of the natural numbers are built.
You probably noticed that prime numbers in the series of natural numbers occur unevenly - in some parts of the series there are more of them, in others - less. But the further we move along the number series, the less common prime numbers are. The question arises: is there a last (largest) prime number? The ancient Greek mathematician Euclid (3rd century BC), in his book “Elements”, which was the main textbook of mathematics for two thousand years, proved that there are infinitely many prime numbers, i.e. behind each prime number there is an even greater prime number.
To find prime numbers, another Greek mathematician of the same time, Eratosthenes, came up with this method. He wrote down all the numbers from 1 to some number, and then crossed out one, which is neither a prime nor a composite number, then crossed out through one all the numbers coming after 2 (numbers that are multiples of 2, i.e. 4, 6 , 8, etc.). The first remaining number after 2 was 3. Then, after two, all numbers coming after 3 (numbers that are multiples of 3, i.e. 6, 9, 12, etc.) were crossed out. in the end only the prime numbers remained uncrossed.
But many natural numbers are also divisible by other natural numbers.
For example:
The number 12 is divisible by 1, by 2, by 3, by 4, by 6, by 12;
The number 36 is divisible by 1, by 2, by 3, by 4, by 6, by 12, by 18, by 36.
The numbers by which the number is divisible by a whole (for 12 these are 1, 2, 3, 4, 6 and 12) are called divisors of numbers. Divisor of a natural number a- is a natural number that divides given number a without a trace. A natural number that has more than two divisors is called composite .
Please note that the numbers 12 and 36 have common factors. These numbers are: 1, 2, 3, 4, 6, 12. The greatest divisor of these numbers is 12. The common divisor of these two numbers a And b- this is the number by which both given numbers are divided without remainder a And b.
Common multiples several numbers is a number that is divisible by each of these numbers. For example, the numbers 9, 18 and 45 have a common multiple of 180. But 90 and 360 are also their common multiples. Among all common multiples there is always a smallest one, in in this case this is 90. This number is called the smallestcommon multiple (CMM).
The LCM is always a natural number that must be greater than the largest of the numbers for which it is defined.
Least common multiple (LCM). Properties.
Commutativity:
Associativity:
In particular, if and are coprime numbers, then:
Least common multiple of two integers m And n is a divisor of all other common multiples m And n. Moreover, the set of common multiples m, n coincides with the set of multiples of the LCM( m, n).
The asymptotics for can be expressed in terms of some number-theoretic functions.
So, Chebyshev function. And:
This follows from the definition and properties of the Landau function g(n).
What follows from the law of distribution of prime numbers.
Finding the least common multiple (LCM).
NOC( a, b) can be calculated in several ways:
1. If the greatest common divisor is known, you can use its connection with the LCM:
2. Let the canonical decomposition of both numbers into prime factors be known:
Where p 1 ,...,p k- various prime numbers, and d 1 ,...,d k And e 1 ,...,e k— non-negative integers (they can be zeros if the corresponding prime is not in the expansion).
Then NOC ( a,b) is calculated by the formula:
In other words, the LCM decomposition contains all prime factors included in at least one of the decompositions of numbers a, b, and the largest of the two exponents of this multiplier is taken.
Example:
Calculating the least common multiple of several numbers can be reduced to several sequential calculations of the LCM of two numbers:
Rule. To find the LCM of a series of numbers, you need:
- decompose numbers into prime factors;
- transfer the largest expansion (the product of the factors of the desired product) into the factors of the desired product large number from the given ones), and then add factors from the expansion of other numbers that do not appear in the first number or appear in it fewer times;
— the resulting product of prime factors will be the LCM of the given numbers.
Any two or more natural numbers have their own LCM. If the numbers are not multiples of each other or do not have the same factors in the expansion, then their LCM is equal to the product of these numbers.
The prime factors of the number 28 (2, 2, 7) are supplemented with the factor 3 (the number 21), the resulting product (84) will be the smallest number, which is divisible by 21 and 28.
The prime factors of the largest number 30 are supplemented by the factor 5 of the number 25, the resulting product 150 is greater than the largest number 30 and is divisible by all given numbers without a remainder. This least product of the possible (150, 250, 300...), to which all given numbers are multiples.
The numbers 2,3,11,37 are prime numbers, so their LCM is equal to the product of the given numbers.
Rule. To calculate the LCM of prime numbers, you need to multiply all these numbers together.
Another option:
To find the least common multiple (LCM) of several numbers you need:
1) represent each number as a product of its prime factors, for example:
504 = 2 2 2 3 3 7,
2) write down the powers of all prime factors:
504 = 2 2 2 3 3 7 = 2 3 3 2 7 1,
3) write down all the prime divisors (multipliers) of each of these numbers;
4) choose the greatest degree of each of them, found in all expansions of these numbers;
5) multiply these powers.
Example. Find the LCM of the numbers: 168, 180 and 3024.
Solution. 168 = 2 2 2 3 7 = 2 3 3 1 7 1,
180 = 2 2 3 3 5 = 2 2 3 2 5 1,
3024 = 2 2 2 2 3 3 3 7 = 2 4 3 3 7 1.
We write out greatest degrees all prime divisors and multiply them:
NOC = 2 4 3 3 5 1 7 1 = 15120.
The material presented below is a logical continuation of the theory from the article entitled LCM - least common multiple, definition, examples, connection between LCM and GCD. Here we will talk about finding the least common multiple (LCM), And Special attention Let's focus on solving examples. First, we will show how the LCM of two numbers is calculated using the GCD of these numbers. Next, we'll look at finding the least common multiple by factoring numbers into prime factors. After this, we will focus on finding the LCM of three or more numbers, and also pay attention to calculating the LCM of negative numbers.
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Calculating Least Common Multiple (LCM) via GCD
One way to find the least common multiple is based on the relationship between LCM and GCD. Existing connection between LCM and GCD allows you to calculate the least common multiple of two positive integers using a known greatest common divisor. The corresponding formula is LCM(a, b)=a b:GCD(a, b) . Let's look at examples of finding the LCM using the given formula.
Example.
Find the least common multiple of two numbers 126 and 70.
Solution.
In this example a=126 , b=70 . Let us use the connection between LCM and GCD, expressed by the formula LCM(a, b)=a b:GCD(a, b). That is, first we have to find the greatest common divisor of the numbers 70 and 126, after which we can calculate the LCM of these numbers using the written formula.
Let's find GCD(126, 70) using the Euclidean algorithm: 126=70·1+56, 70=56·1+14, 56=14·4, therefore, GCD(126, 70)=14.
Now we find the required least common multiple: GCD(126, 70)=126·70:GCD(126, 70)= 126·70:14=630.
Answer:
LCM(126, 70)=630 .
Example.
What is LCM(68, 34) equal to?
Solution.
Because 68 is divisible by 34, then GCD(68, 34)=34. Now we calculate the least common multiple: GCD(68, 34)=68·34:GCD(68, 34)= 68·34:34=68.
Answer:
LCM(68, 34)=68 .
Note that the previous example fits the following rule for finding the LCM for positive integers a and b: if the number a is divisible by b, then the least common multiple of these numbers is a.
Finding the LCM by factoring numbers into prime factors
Another way to find the least common multiple is based on factoring numbers into prime factors. If you compose a product from all the prime factors of given numbers, and then exclude from this product all the common prime factors present in the decompositions of the given numbers, then the resulting product will be equal to the least common multiple of the given numbers.
The stated rule for finding the LCM follows from the equality LCM(a, b)=a b:GCD(a, b). Indeed, the product of numbers a and b is equal to the product of all factors involved in the expansion of numbers a and b. In turn, GCD(a, b) is equal to the product of all prime factors simultaneously present in the expansions of numbers a and b (as described in the section on finding GCD using the expansion of numbers into prime factors).
Let's give an example. Let us know that 75=3·5·5 and 210=2·3·5·7. Let's compose the product from all the factors of these expansions: 2·3·3·5·5·5·7 . Now from this product we exclude all the factors present in both the expansion of the number 75 and the expansion of the number 210 (these factors are 3 and 5), then the product will take the form 2·3·5·5·7. The value of this product is equal to the least common multiple of 75 and 210, that is, NOC(75, 210)= 2·3·5·5·7=1,050.
Example.
Factor the numbers 441 and 700 into prime factors and find the least common multiple of these numbers.
Solution.
Let's factor the numbers 441 and 700 into prime factors:
We get 441=3·3·7·7 and 700=2·2·5·5·7.
Now let’s create a product from all the factors involved in the expansion of these numbers: 2·2·3·3·5·5·7·7·7. Let us exclude from this product all factors that are simultaneously present in both expansions (there is only one such factor - this is the number 7): 2·2·3·3·5·5·7·7. Thus, LCM(441, 700)=2·2·3·3·5·5·7·7=44 100.
Answer:
NOC(441, 700)= 44 100 .
The rule for finding the LCM using factorization of numbers into prime factors can be formulated a little differently. If the missing factors from the expansion of number b are added to the factors from the expansion of the number a, then the value of the resulting product will be equal to the least common multiple of the numbers a and b.
For example, let's take the same numbers 75 and 210, their decompositions into prime factors are as follows: 75=3·5·5 and 210=2·3·5·7. To the factors 3, 5 and 5 from the expansion of the number 75 we add the missing factors 2 and 7 from the expansion of the number 210, we obtain the product 2·3·5·5·7, the value of which is equal to LCM(75, 210).
Example.
Find the least common multiple of 84 and 648.
Solution.
We first obtain the decompositions of the numbers 84 and 648 into prime factors. They look like 84=2·2·3·7 and 648=2·2·2·3·3·3·3. To the factors 2, 2, 3 and 7 from the expansion of the number 84 we add the missing factors 2, 3, 3 and 3 from the expansion of the number 648, we obtain the product 2 2 2 3 3 3 3 7, which is equal to 4 536 . Thus, the desired least common multiple of 84 and 648 is 4,536.
Answer:
LCM(84, 648)=4,536 .
Finding the LCM of three or more numbers
The least common multiple of three or more numbers can be found by sequentially finding the LCM of two numbers. Let us recall the corresponding theorem, which gives a way to find the LCM of three or more numbers.
Theorem.
Let positive integer numbers a 1 , a 2 , …, a k be given, the least common multiple m k of these numbers is found by sequentially calculating m 2 = LCM(a 1 , a 2) , m 3 = LCM(m 2 , a 3) , … , m k = LCM(m k−1 , a k) .
Let's consider the application of this theorem using the example of finding the least common multiple of four numbers.
Example.
Find the LCM of four numbers 140, 9, 54 and 250.
Solution.
In this example, a 1 =140, a 2 =9, a 3 =54, a 4 =250.
First we find m 2 = LOC(a 1 , a 2) = LOC(140, 9). To do this, using the Euclidean algorithm, we determine GCD(140, 9), we have 140=9·15+5, 9=5·1+4, 5=4·1+1, 4=1·4, therefore, GCD(140, 9)=1 , from where GCD(140, 9)=140 9:GCD(140, 9)= 140·9:1=1,260. That is, m 2 =1 260.
Now we find m 3 = LOC (m 2 , a 3) = LOC (1 260, 54). Let's calculate it through GCD(1 260, 54), which we also determine using the Euclidean algorithm: 1 260=54·23+18, 54=18·3. Then gcd(1,260, 54)=18, from which gcd(1,260, 54)= 1,260·54:gcd(1,260, 54)= 1,260·54:18=3,780. That is, m 3 =3 780.
All that remains is to find m 4 = LOC(m 3, a 4) = LOC(3 780, 250). To do this, we find GCD(3,780, 250) using the Euclidean algorithm: 3,780=250·15+30, 250=30·8+10, 30=10·3. Therefore, GCM(3,780, 250)=10, whence GCM(3,780, 250)= 3 780 250: GCD(3 780, 250)= 3,780·250:10=94,500. That is, m 4 =94,500.
So the least common multiple of the original four numbers is 94,500.
Answer:
LCM(140, 9, 54, 250)=94,500.
In many cases, it is convenient to find the least common multiple of three or more numbers using prime factorizations of the given numbers. In this case, you should adhere to the following rule. The least common multiple of several numbers is equal to the product, which is composed as follows: the missing factors from the expansion of the second number are added to all factors from the expansion of the first number, the missing factors from the expansion of the third number are added to the resulting factors, and so on.
Let's look at an example of finding the least common multiple using prime factorization.
Example.
Find the least common multiple of the five numbers 84, 6, 48, 7, 143.
Solution.
First, we obtain decompositions of these numbers into prime factors: 84=2·2·3·7, 6=2·3, 48=2·2·2·2·3, 7 (7 is a prime number, it coincides with its decomposition into prime factors) and 143=11·13.
To find the LCM of these numbers, to the factors of the first number 84 (they are 2, 2, 3 and 7), you need to add the missing factors from the expansion of the second number 6. The decomposition of the number 6 does not contain missing factors, since both 2 and 3 are already present in the decomposition of the first number 84. Next, to the factors 2, 2, 3 and 7 we add the missing factors 2 and 2 from the expansion of the third number 48, we get a set of factors 2, 2, 2, 2, 3 and 7. There will be no need to add multipliers to this set in the next step, since 7 is already contained in it. Finally, to the factors 2, 2, 2, 2, 3 and 7 we add the missing factors 11 and 13 from the expansion of the number 143. We get the product 2·2·2·2·3·7·11·13, which is equal to 48,048.
Second number: b=
Thousand separator Without space separator "´
Result:
Greatest common divisor gcd( a,b)=6
Least common multiple of LCM( a,b)=468
The largest natural number that can be divided without a remainder by numbers a and b is called greatest common divisor(GCD) of these numbers. Denoted by gcd(a,b), (a,b), gcd(a,b) or hcf(a,b).
Least common multiple The LCM of two integers a and b is the smallest natural number that is divisible by a and b without a remainder. Denoted LCM(a,b), or lcm(a,b).
The integers a and b are called mutually prime, if they have no common divisors other than +1 and −1.
Greatest common divisor
Let two positive numbers be given a 1 and a 2 1). It is required to find the common divisor of these numbers, i.e. find such a number λ , which divides numbers a 1 and a 2 at the same time. Let's describe the algorithm.
1) In this article, the word number will be understood as an integer.
Let a 1 ≥ a 2 and let
Where m 1 , a 3 are some integers, a 3 <a 2 (remainder of division a 1 per a 2 should be less a 2).
Let's pretend that λ divides a 1 and a 2 then λ divides m 1 a 2 and λ divides a 1 −m 1 a 2 =a 3 (Statement 2 of the article “Divisibility of numbers. Divisibility test”). It follows that every common divisor a 1 and a 2 is the common divisor a 2 and a 3. The reverse is also true if λ common divisor a 2 and a 3 then m 1 a 2 and a 1 =m 1 a 2 +a 3 is also divisible by λ . Therefore the common divisor a 2 and a 3 is also a common divisor a 1 and a 2. Because a 3 <a 2 ≤a 1, then we can say that the solution to the problem of finding the common divisor of numbers a 1 and a 2 reduced to the simpler problem of finding the common divisor of numbers a 2 and a 3 .
If a 3 ≠0, then we can divide a 2 on a 3. Then
,
Where m 1 and a 4 are some integers, ( a 4 remainder from division a 2 on a 3 (a 4 <a 3)). By similar reasoning we come to the conclusion that common divisors of numbers a 3 and a 4 coincides with common divisors of numbers a 2 and a 3, and also with common divisors a 1 and a 2. Because a 1 , a 2 , a 3 , a 4, ... are numbers that are constantly decreasing, and since there is a finite number of integers between a 2 and 0, then at some step n, remainder of the division a n on a n+1 will be equal to zero ( a n+2 =0).
.
Every common divisor λ numbers a 1 and a 2 is also a divisor of numbers a 2 and a 3 , a 3 and a 4 , .... a n and a n+1 . The converse is also true, common divisors of numbers a n and a n+1 are also divisors of numbers a n−1 and a n , .... , a 2 and a 3 , a 1 and a 2. But the common divisor of numbers a n and a n+1 is a number a n+1 , because a n and a n+1 are divisible by a n+1 (remember that a n+2 =0). Hence a n+1 is also a divisor of numbers a 1 and a 2 .
Note that the number a n+1 is the largest divisor of numbers a n and a n+1 , since the greatest divisor a n+1 is itself a n+1 . If a n+1 can be represented as a product of integers, then these numbers are also common divisors of numbers a 1 and a 2. Number a n+1 is called greatest common divisor numbers a 1 and a 2 .
Numbers a 1 and a 2 can be either positive or negative numbers. If one of the numbers is equal to zero, then the greatest common divisor of these numbers will be equal to the absolute value of the other number. The greatest common divisor of zero numbers is undefined.
The above algorithm is called Euclidean algorithm to find the greatest common divisor of two integers.
An example of finding the greatest common divisor of two numbers
Find the greatest common divisor of two numbers 630 and 434.
- Step 1. Divide the number 630 by 434. The remainder is 196.
- Step 2. Divide the number 434 by 196. The remainder is 42.
- Step 3. Divide the number 196 by 42. The remainder is 28.
- Step 4. Divide the number 42 by 28. The remainder is 14.
- Step 5. Divide the number 28 by 14. The remainder is 0.
In step 5, the remainder of the division is 0. Therefore, the greatest common divisor of the numbers 630 and 434 is 14. Note that the numbers 2 and 7 are also divisors of the numbers 630 and 434.
Coprime numbers
Definition 1. Let the greatest common divisor of the numbers a 1 and a 2 is equal to one. Then these numbers are called coprime numbers, having no common divisor.
Theorem 1. If a 1 and a 2 coprime numbers, and λ some number, then any common divisor of numbers λa 1 and a 2 is also a common divisor of numbers λ And a 2 .
Proof. Consider the Euclidean algorithm for finding the greatest common divisor of numbers a 1 and a 2 (see above).
.
From the conditions of the theorem it follows that the greatest common divisor of the numbers a 1 and a 2 and therefore a n and a n+1 is 1. That is a n+1 =1.
Let's multiply all these equalities by λ , Then
.
Let the common divisor a 1 λ And a 2 yes δ . Then δ is included as a multiplier in a 1 λ , m 1 a 2 λ and in a 1 λ -m 1 a 2 λ =a 3 λ (see "Divisibility of numbers", Statement 2). Further δ is included as a multiplier in a 2 λ And m 2 a 3 λ , and, therefore, is a factor in a 2 λ -m 2 a 3 λ =a 4 λ .
Reasoning this way, we are convinced that δ is included as a multiplier in a n−1 λ And m n−1 a n λ , and therefore in a n−1 λ −m n−1 a n λ =a n+1 λ . Because a n+1 =1, then δ is included as a multiplier in λ . Therefore the number δ is the common divisor of numbers λ And a 2 .
Let us consider special cases of Theorem 1.
Consequence 1. Let a And c Prime numbers are relatively b. Then their product ac is a prime number with respect to b.
Really. From Theorem 1 ac And b have the same common divisors as c And b. But the numbers c And b relatively simple, i.e. have a single common divisor 1. Then ac And b also have a single common divisor 1. Therefore ac And b mutually simple.
Consequence 2. Let a And b coprime numbers and let b divides ak. Then b divides and k.
Really. From the approval condition ak And b have a common divisor b. By virtue of Theorem 1, b must be a common divisor b And k. Hence b divides k.
Corollary 1 can be generalized.
Consequence 3. 1. Let the numbers a 1 , a 2 , a 3 , ..., a m are prime relative to the number b. Then a 1 a 2 , a 1 a 2 · a 3 , ..., a 1 a 2 a 3 ··· a m, the product of these numbers is prime with respect to the number b.
2. Let us have two rows of numbers
such that every number in the first series is prime in the ratio of every number in the second series. Then the product
You need to find numbers that are divisible by each of these numbers.
If a number is divisible by a 1, then it has the form sa 1 where s some number. If q is the greatest common divisor of numbers a 1 and a 2, then
Where s 1 is some integer. Then
is least common multiples of numbers a 1 and a 2 .
a 1 and a 2 are relatively prime, then the least common multiple of the numbers a 1 and a 2:
We need to find the least common multiple of these numbers.
From the above it follows that any multiple of numbers a 1 , a 2 , a 3 must be a multiple of numbers ε And a 3 and back. Let the least common multiple of the numbers ε And a 3 yes ε 1 . Next, multiples of numbers a 1 , a 2 , a 3 , a 4 must be a multiple of numbers ε 1 and a 4 . Let the least common multiple of the numbers ε 1 and a 4 yes ε 2. Thus, we found out that all multiples of numbers a 1 , a 2 , a 3 ,...,a m coincide with multiples of a certain number ε n, which is called the least common multiple of the given numbers.
In the special case when the numbers a 1 , a 2 , a 3 ,...,a m are relatively prime, then the least common multiple of the numbers a 1 , a 2, as shown above, has the form (3). Next, since a 3 prime in relation to numbers a 1 , a 2 then a 3 prime number a 1 · a 2 (Corollary 1). Means the least common multiple of numbers a 1 ,a 2 ,a 3 is a number a 1 · a 2 · a 3. Reasoning in a similar way, we arrive at the following statements.
Statement 1. Least common multiple of coprime numbers a 1 , a 2 , a 3 ,...,a m is equal to their product a 1 · a 2 · a 3 ··· a m.
Statement 2. Any number that is divisible by each of the coprime numbers a 1 , a 2 , a 3 ,...,a m is also divisible by their product a 1 · a 2 · a 3 ··· a m.
Greatest common divisor and least common multiple are key arithmetic concepts that make working with fractions effortless. LCM and are most often used to find the common denominator of several fractions.
Basic Concepts
The divisor of an integer X is another integer Y by which X is divided without leaving a remainder. For example, the divisor of 4 is 2, and 36 is 4, 6, 9. A multiple of an integer X is a number Y that is divisible by X without a remainder. For example, 3 is a multiple of 15, and 6 is a multiple of 12.
For any pair of numbers we can find their common divisors and multiples. For example, for 6 and 9, the common multiple is 18, and the common divisor is 3. Obviously, pairs can have several divisors and multiples, so the calculations use the largest divisor GCD and the smallest multiple LCM.
The least divisor is meaningless, since for any number it is always one. The greatest multiple is also meaningless, since the sequence of multiples goes to infinity.
Finding gcd
There are many methods for finding the greatest common divisor, the most famous of which are:
- sequential search of divisors, selection of common ones for a pair and search for the largest of them;
- decomposition of numbers into indivisible factors;
- Euclidean algorithm;
- binary algorithm.
Today in educational institutions the most popular methods are decomposition into prime factors and the Euclidean algorithm. The latter, in turn, is used when solving Diophantine equations: searching for GCD is required to check the equation for the possibility of resolution in integers.
Finding the NOC
The least common multiple is also determined by sequential search or decomposition into indivisible factors. In addition, it is easy to find the LCM if the greatest divisor has already been determined. For numbers X and Y, the LCM and GCD are related by the following relationship:
LCD(X,Y) = X × Y / GCD(X,Y).
For example, if GCM(15,18) = 3, then LCM(15,18) = 15 × 18 / 3 = 90. The most obvious example of using LCM is to find the common denominator, which is the least common multiple of given fractions.
Coprime numbers
If a pair of numbers has no common divisors, then such a pair is called coprime. The gcd for such pairs is always equal to one, and based on the connection between divisors and multiples, the gcd for coprime pairs is equal to their product. For example, the numbers 25 and 28 are relatively prime, because they have no common divisors, and LCM(25, 28) = 700, which corresponds to their product. Any two indivisible numbers will always be relatively prime.
Common divisor and multiple calculator
Using our calculator you can calculate GCD and LCM for an arbitrary number of numbers to choose from. Tasks on calculating common divisors and multiples are found in 5th and 6th grade arithmetic, but GCD and LCM are key concepts in mathematics and are used in number theory, planimetry and communicative algebra.
Real life examples
Common denominator of fractions
Least common multiple is used when finding the common denominator of multiple fractions. Let's say in an arithmetic problem you need to sum 5 fractions:
1/8 + 1/9 + 1/12 + 1/15 + 1/18.
To add fractions, the expression must be reduced to a common denominator, which reduces to the problem of finding the LCM. To do this, select 5 numbers in the calculator and enter the values of the denominators in the corresponding cells. The program will calculate the LCM (8, 9, 12, 15, 18) = 360. Now you need to calculate additional factors for each fraction, which are defined as the ratio of the LCM to the denominator. So the additional multipliers would look like:
- 360/8 = 45
- 360/9 = 40
- 360/12 = 30
- 360/15 = 24
- 360/18 = 20.
After this, we multiply all the fractions by the corresponding additional factor and get:
45/360 + 40/360 + 30/360 + 24/360 + 20/360.
We can easily sum such fractions and get the result as 159/360. We reduce the fraction by 3 and see the final answer - 53/120.
Solving linear Diophantine equations
Linear Diophantine equations are expressions of the form ax + by = d. If the ratio d / gcd(a, b) is an integer, then the equation is solvable in integers. Let's check a couple of equations to see if they have an integer solution. First, let's check the equation 150x + 8y = 37. Using a calculator, we find GCD (150.8) = 2. Divide 37/2 = 18.5. The number is not an integer, therefore the equation does not have integer roots.
Let's check the equation 1320x + 1760y = 10120. Use a calculator to find GCD(1320, 1760) = 440. Divide 10120/440 = 23. As a result, we get an integer, therefore, the Diophantine equation is solvable in integer coefficients.
Conclusion
GCD and LCM play a big role in number theory, and the concepts themselves are widely used in a wide variety of areas of mathematics. Use our calculator to calculate the greatest divisors and least multiples of any number of numbers.